let the 1st throw be x

2nd......................5x

3rd......................5x-6

4th....................(5x-6)+11

5th....................[(5x-6)+11]-8

The posible outcome for a dice thrown 5 times is :

12 times 5= 60

now, [(5x-6)+11]-8 = 60

[(5x-6)+11] = 68

b4 i continue , am i getting somewhere, IG ?